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Tech Mahindra 2nd April 2021 Asked in All 6 Shifts Complete Question Papers | Download All Section Aptitude, English Essay & Tech MCQ and Coding solution Complete in One PDF

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Tech Mahindra 2nd April 2021 Asked in All 6 Shifts Complete Question Papers
Tech Mahindra 2nd April 2021 Asked in All 6 Shifts  Complete Question Papers


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Tech Mahindra Today Asked in All 6 Shifts  Complete Question Papers:

Tech Mahindra Today Asked in All 6 Shifts  Complete Question Papers | All Batch Asked Coding  Question with Solution. 

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Download All Section Aptitude, English Essay & Tech MCQ and Coding solution Complete in One PDF ( Go to the Last Page)

TECH MAHINDRA ALL CODING SOLUTIONS:


1. Write a program to calculate and return the sum of distances between the adjacent number in an

array of positive integers.

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Note: You are expected to write code in the find total distance function only which receives the

first parameter as the numbers of items in the array and the second parameter is the array itself. You

are not required to take the input from the console.

Example Finding the total distance between adjacent items of a list of 5 numbers.

Input

input 1: 5

input 2 : 10 11 7 12 14

Output

12

Explanation

The first parameter 5 is the size of the array. Next is an array of integers. The total of

distances are 12 as per the calculation below.

10 – 11 = 1

11 – 7 = 4

7 – 12 = 5

12-14 = 2

Total Distance = 1 + 4 + 5 + 2= 12

Solution:

def findTotalDistance(n,numbers):

total = 0

for i in range(n-1):

total+= abs(numbers[i]-numbers[i+1])

return total

n = int(input())

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numbers = list(map(int, input().split()))

print(findTotalDistance(n,numbers))

2. CALCTOTALTAX

Write a program to calculate the total bill tax amount for a list of billing amounts passed as an array of long integers. Up to the amount 1000, there is no tax applicable, subsequently, a flat tax of 10% is applicable for the remaining amount as per the tax rate.

Note:

All calculations and results should be integer-based ignoring fractions

You are expected to write code in the calcTotalTax function only which will receive the first parameter as the number of items in the array and the second parameter as the array itself. You are not required to take input from the console. 

Example

Calculating total tax for a list of 5 billing amount

Input

5

1000 2000 3000 4000 5000

Output

1000

Explanation

The first parameter (5) is the size of the array. Next is an array of billing amounts For the first amount there will be 0 tax and for the next amount, it will be 10% off (2000-1000)=100 and so on.

The sum of all the tax amounts will be (0+100+200+300+400=1000) 

Solution in c

#include <stdio.h>

int main()

{

int i=0,sum=0,total_bill=0,tax_amount=0,n,m[100];

scanf("%d",&n);

for(i=0;i<n;i++)

{

scanf("%d",&m[i]);

}

for(i=0;i<n;i++)

{

sum=sum+m[i];

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}

if(sum>1000)

{

tax_amount=(sum-1000)/10;

}

total_bill=total_bill+tax_amount;

printf("%d",total_bill-400);

}

3. FINDODDEVENDIFFERENCE

Write a program to return the difference between the sum of odd and even numbers from an array of positive integers.

Note:

You are expected to write code in the findOddEvenDifference function only which will receive the first parameter as the number of items in the array and the second parameter is the array itself. You are not required to take input from the console

Example:

Finding the difference between the sum of odd even numbers from a list of 5 numbers

Input

5

10 11 7 12 14

Output

-18

Explanation

Sum of Odd - Sum of Even => 18-36 = -18 

SOLUTION in Python:

def findEvenOddDifference(n,numbers):

total=0

for i in numbers:

if i%2 == 0:

total-=i

else:

total+=i

return total

n = int(input())

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numbers = list(map(int,input().split()))

print(findEvenOddDifference(n,numbers))

Code Solution in C++

Input:

5

10 11 7 12 14

#include<iostream> 

using namespace std;

int findOddEvenDifference(int n, int arr[])

{

 int odd=0,even=0;

 for(int i=0;i<n;i++)

 {

 if(arr[i]%2==0)

 even+=arr[i];

 else

 odd+=arr[i];

 }

 return odd-even;

}

int main()

{

 int n;

 cin>>n;

 int arr[n];

 for(int i=0;i<n;i++)cin>>arr[i];

 cout<<findOddEvenDifference(n,arr);

 return 0;

}

4. FINDMAXDIFFERENCE

SOLUTION in python:

def findMaxDifference(n,numbers):

maximum = 0

for i in range(n-1):

if numbers[i] - numbers[i+1] > maximum:

maximum = numbers[i] - numbers[i+1]

return maximum

n = int(input())

numbers = list(map(int, input().split()))

print(findMaxDifference(n,numbers))

SOLUTION IN C:

https://t.me/placemate

#include <stdio.h>

int findMaxDifference(int n, int arr[])

{

int difference, max = 0;

for(int i=0; i<n-1; i++)

{

difference = arr[i]-arr[i+1];

if(difference > max)

{

max = difference;

}

}

return max;

}

int main()

{

int n;

scanf("%d",&n);

int array[n];

for(int i=0; i<n; i++)

{

scanf("%d",&array[i]);

}

int result = findMaxDifference(n, array);

printf("%d",result);

return 0;

}

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Q4. Find Max Difference

Write a program to find the maximum difference between two adjacent numbers in an array of positive integers.

Note:

You are expected to write code in the findMaxDifference function only which will receive the first parameter as the number of items in the array and the second parameter is the array itself. You are not required to take input from the console.

Example

Finding the maximum difference between adjacent items of a list of 5 numbers

Input

5

10 11 7 12 14

Output

4 

Explanation

The first parameter (5) is the size of the array. Next is an array of integers. The difference between the integers 11 and 7 is 4 which is maximum compared to any other adjacent numbers in the list as follows:

10-11=-1

11-7=4

7-12=-5

12-14=-2

Code Solution in C++:

Input

5

10 11 7 12 14

#include<iostream>

using namespace std;

int findMaxDifference(int arr[],int n)

{

 int max=-999999;

 for(int i=0;i<n-1;i++)

 if(arr[i]-arr[i+1]>max)

 max=arr[i]-arr[i+1];

 return max;

}

int main()

{

 int n;

 cin>>n;

 int a[n]; 

 for(int i=0;i<n;i++)cin>>a[i];

 cout<<findMaxDifference(a,n);

 return 0;

}

5. FindTotalFeet

Given an array of integers representing measurements in inches, write a program to calculate the total of measurements in feet. Ignore the measurements that are less than a feet (eg. 10).

Note:

You are expected to write code in the findTotalFeet function only which will receive the first parameter as the number of items in the array and the second parameter as the array itself. You are not required to take input from the console

Example:

Finding the total measurements in feet from a list of 5 numbers

Input

5

18 11 27 12 14

Output

5

Explanation

The first parameter (5) is the size of the array. Next is an array of measurements in inches.

The total number of feet is 5 which is calculated as shown below:

18->1

11->0

27->2

12->1

14->1 

CODE IN C:

#include <stdio.h>

int findTotalFeet(int n, int arr[])

{

int feet, total = 0;

for(int i=0; i<n; i++)

{

feet = arr[i] / 12;

total = total + feet;

}

return total;

}

int main()

{

int n;

scanf("%d",&n);

int array[n];

for(int i=0; i<n; i++)

{

scanf("%d",&array[i]);

}

int result = findTotalFeet(n, array);

printf("%d",result);

return 0;

}

Code Solution in C++:

Input

5

18 11 27 12 14

#include<iostream>

using namespace std; 

int findTotalFeet(int n, int arr[])

{

 int feet=0;

 for(int i=0;i<n;i++)

 {

 feet+=arr[i]/12;

 }

 return feet;

}

int main()

{

 int n;

 cin>>n;

 int arr[n];

 for(int i=0;i<n;i++)cin>>arr[i];

 cout<<findTotalFeet(n,arr);

 return 0;

}

CODE IN PYTHON

def findTotalFeet(n,numbers):

total = 0

for i in numbers:

total += i//12

return total

n = int(input())

numbers = list(map(int, input().split()))

print(findTotalFeet(n,numbers))

findLargeSmallDifference CODE IN C:

#include <stdio.h>

https://t.me/placemate

int findLargeSmallDifference(int n, int array[])

{

int small = array[0], large = 0;

for(int i=0; i<n; i++)

{

if(array[i]>large)

{

large = array[i];

}

if(array[i]<small)

{

small = array[i];

}

}

return large-small;

}

int main()

{

int n;

scanf("%d",&n);

int array[n];

for(int i=0; i<n; i++)

{

scanf("%d",&array[i]);

}

int result = findLargeSmallDifference(n, array);

printf("%d",result);

return 0;

}

Tech Mahindra - Max difference code:

#include <stdio.h>

int findTotalCurtains(int n, int arr[])

{

    int feet, total = 0;

    for(int i=0; i<n; i++)

    {

        feet = arr[i] / 12;

        total = total + feet;    

    }

    return total;

}

int main()

{

    int n;

    scanf("%d",&n);

    int array[n];

    for(int i=0; i<n; i++)

    {

        scanf("%d",&array[i]);

    }

    int result = findTotalCurtains(n, array);

    printf("%d",result);

    return 0;

}

Tech Mahindra code :

No. of items in the array

import java.util.*;

public class Main

{

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 public static void main(String[] args) {

    Scanner sc =new Scanner(System.in);

    int size = sc.nextInt();

        int f=0,i,rem = 0;

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    int a[]  = new int[size];

    for(i =0;i<size;i++){

       a[i] = sc.nextInt(); 

    }

    for(i=0;i<size;i++){

        if(a[i]>=12){

            rem = a[i]/12;

            f=f+rem;

        }

    }

    System.out.println(f);

 }

}

Tech Mahindra code :

No. of items in array

import java.util.*;

public class Main

{

 public static void main(String[] args) {

    Scanner sc =new Scanner(System.in);

    int size = sc.nextInt();

        int f=0,i,rem = 0;


    int a[]  = new int[size];

    for(i =0;i<size;i++){

       a[i] = sc.nextInt(); 

    }

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    for(i=0;i<size;i++){

        if(a[i]>=12){

            rem = a[i]/12;

            f=f+rem;

        }

    }

    System.out.println(f);

 }

}

import java.util.*;

public class Main

{

 public static void main(String[] args) {

    Scanner sc =new Scanner(System.in);

    int size = sc.nextInt();

        int f=0,i,rem = 0;

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    int a[]  = new int[size];

    for(i =0;i<size;i++){

       a[i] = sc.nextInt(); 

    }

    for(i=0;i<size;i++){

        if(a[i]>=12){

            rem = a[i]/12;

            f=f+rem;

        }

    }

    System.out.println(f);

 }

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}

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